PioneerPrepGet started

left = mid + 1;

O(n log n)

const memo = new Map();

while (l < r) { mid = (l+r)/2; }

return dfs(root.left) + dfs(root.right);

def solve(nums):

left = mid + 1;

stack.push(node);

for (int i=0; i<n; i++) {

left = mid + 1;

swap(a[i], a[j]);

graph[u].push_back(v);

map<int,int> freq;

return root == null;

prefix[i] = prefix[i-1] + a[i];

if (visited[u]) continue;

return root == null;

O(n log n)

Job Intelligence · Refreshed daily

India roles that actually match your resume.

Live-scraped from Greenhouse, Lever, Ashby, Workday, and official careers pages. Every job links straight to the company's application page — never a third-party tracker.

You're on free

Free plan shows 2 roles with names, salaries, and apply links hidden. Resume Pro unlocks the full feed.

Upgrade — ₹299/mo

Loading matched roles…